Bonjour, 1) (x+1)(3x?2) = 0 <=>(x+1) ou (3x?2) = 0 <=> x+1=0 ou 3x-2=0 <=>x+1-1=0-1 ou 3x-2=0+2 <=>x=-1 ou 3x=2 <=>x=-1 ou x=2/3 Solution: -1 et 2/3 2) x²?6x+9
Mathématiques
Khamisi242
Question
Bonjour,
1) (x+1)(3x?2) = 0
<=>(x+1) ou (3x?2) = 0
<=> x+1=0 ou 3x-2=0
<=>x+1-1=0-1 ou 3x-2=0+2
<=>x=-1 ou 3x=2
<=>x=-1 ou x=2/3
Solution: -1 et 2/3
2)
x²?6x+9 = 0
<=>(x-3)²=0
<=>(x-3)*'x-3=0
<=>x-3=0
<=>x=3
Solution:3
3)
<=> 2x-V3 = 0
<=> 2x-V3 = 0+V3
<=>2x=-V3
<=>x=-V3/2
solution=-V3/2
4)3x?5 =15
<=>3x-5=15
<=>3x-5+5=15+5
<=>3x=20
<=>x=20/3
Est ce que c'est bon?
1) (x+1)(3x?2) = 0
<=>(x+1) ou (3x?2) = 0
<=> x+1=0 ou 3x-2=0
<=>x+1-1=0-1 ou 3x-2=0+2
<=>x=-1 ou 3x=2
<=>x=-1 ou x=2/3
Solution: -1 et 2/3
2)
x²?6x+9 = 0
<=>(x-3)²=0
<=>(x-3)*'x-3=0
<=>x-3=0
<=>x=3
Solution:3
3)
<=> 2x-V3 = 0
<=> 2x-V3 = 0+V3
<=>2x=-V3
<=>x=-V3/2
solution=-V3/2
4)3x?5 =15
<=>3x-5=15
<=>3x-5+5=15+5
<=>3x=20
<=>x=20/3
Est ce que c'est bon?
1 Réponse
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1. Réponse Anonyme
1) (x+1)(3x-2) = 0
<=>(x+1) ou (3x-2) = 0
<=> x+1=0 ou 3x-2=0
<=>x+1-1=0-1 ou 3x-2=0+2
<=>x=-1 ou 3x=2
<=>x=-1 ou x=2/3
Solutions : -1 et 2/3
2) x²-6x+9 = 0
<=>(x-3)²=0
<=>(x-3)*(x-3)=0
<=>x-3=0
<=>x=3
Solution:3
3) 2x-V3 = 0
<=> 2x-V3 +V3 = 0+V3
<=>2x=V3
<=>x=V3/2
Solution : V3/2
4) 3x-5=15
<=>3x-5+5=15+5
<=>3x=20
<=>x=20/3
Solution : 20/3