Aidez moi svp, developpement, calcul litteral,je n'y arrive pas: '(

bonjour

numéro 2

a = ( x + 1)² + ( x - 3)²
= x² + 2 x + 1 + x² - 6 x + 9
= 2 x² - 4 x + 10

b= (3 - x)² + ( x + 5)²
b = 9 - 6 x + x² + x² + 10 x + 25
b = 2 x² + 4 x + 34

c = ( x - 2)² + ( x + 4) ( x - 4) 
c = x² - 4 x + 4 + x² - 16
c =  2 x² - 4 x  - 12

d = ( x +1) ( x - 1) + ( x + 4)²
d = x² - 1 + x² + 8 x + 16
d = 2 x² + 8 x + 15

e = ( x -5)² + ( 2 x + 7) ( 2 x - 7)
e = x² - 10 x + 25 + 4 x² - 49
e = 5 x² - 10 x - 14

numéro 1

a = ( x + 4)²
a = x² + 8 x + 16

b = ( 2 - x)²
b = 4 - 4 x + x²

c = je ne lis pas le début

d = ( 2 x + 1)² = 4 x² + 4 x + 1

e= ( 3 - 2 x)²
e = 9 - 12 x + 4 x²

f = ( 7 x + 5)²
f = 49 x² + 70 x + 25

g = ( 5 x + 6) ( 5 x -6)
g = 25 x ² - 36

h = ( 4 - 8 x)²
h = 16 - 64 x + 64 x²

g = ( 3 + 4 x) ( 3 + 4x)
g = 9 + 12 x + 12 x + 16 x²
g = 16 x² + 24 x + 9

j = ( 3 + x) ( x - 3)
j = 3 x - 9 + x² - 3 x
j = x² - 9

k = ( 2 + 9 x)²
k = 4 + 36 x + 81 x²

i = ( 11 x - 12)²
i = 121 x² - 264 x  + 144


numéro 3

a = ( 2 x + 1)² - ( x + 3)²
a = ( 4 x² + 4 x + 1 ) - ( x² + 6 x + 9)
a = 4 x² + 4 x + 1 - x² - 6 x - 9
a = 3 x² - 2 x - 8

b = (2 x + 3)² - ( x-7) ( x + 7)
b = 4 x² + 12 x + 9 - ( x² - 49)
b = 4 x² + 12 x + 9 - x² + 49
b = 3 x² + 12 x + 58

c = ( x +2) ( x - 2) - ( x - 3)²
c = ( x² - 4) - ( x² - 6 x + 9)
c = x² - 4 - x² + 6 x - 9
c = 6 x - 13

d = ( x - 5)² - ( 2 x - 7) ( x - 5)
d = x² - 10 x +25 - ( 2 x² - 10 x - 7 x + 35)
d = x² - 10 x + 25 - 2 x² + 10 x + 7 x - 35
d = - x² + 7 x - 10

e = ( 3 x + 1) ( x - 2) - ( 2 x - 3)²
e = 3 x² - 6 x + x - 2 - ( 4 x² - 12 x + 9)
e = 3 x² - 5 x - 2 - 4 x² + 12 x - 9
e = - x² + 7 x - 11