Résoudre l'équation : [tex] x^{2} [/tex]+2x+6=2x(x-2)

x² +2x +6 = 2x(x - 2)
x² + 2x + 6 = 2x² - 4x
x² + 2x + 6 - 2x² + 4x = 0
- x² + 6x + 6 = 0

Δ = b² - 4ac
Δ = (6)² − (4×(-1)×6)
Δ = 60

√ Δ  =√60 = √(4 x 15) = 2√15

x1 = (-b − √Δ)/2a
x1 = (-6 − 2√15) / (-2)
x1 = (-6)/ (-2)  − 2√15 / (-2)
x1 =  3 + √15

x2 = (-b + √Δ)/2a
x2 = (-6 + 2√15) / (-2)
x2 = (-6)/ (-2)  + 2√15 / (-2)
x2 =  3 - √15