It is given that y=k/x that y=5 when x=9 Find the (i) value of y when x =36 (ii) value of x when y = 15

Find the value of k :
[tex]5=\frac{k}{9}[/tex]
[tex] k = 5*9[/tex]
[tex] k=45[/tex]

If x=36 :
[tex]y=\frac{45}{36}[/tex]
[tex]y=1.25[/tex]

If y=15 :
[tex]15=\frac{45}{x}[/tex]
[tex] \frac{1}{x}=\frac{15}{45}[/tex]
[tex] x = 3 [/tex]