bonjour. pouvez-vous me réalisé ces exercices svp.

Bonjour,

4/(a-1) - 5/(a-2) = [4(a-2)-5(a-1)] / [(a-1)(a-2)] = (-a-3)/(a²-3a+2)

[(a-b)/2a ] * [ 4/(a-b)] * a = 4a / 2a = 2 

[ (a²-2ab+b²)/(xy) ] / [ (a-b)/x² ] = [(a-b)x] / y 

[(x+3)/(x+3)²] * [ (x-3)(x+3) / (x-3)] = [ 1/(x+3) ] * (x+3) = 1 

[ 2/(x+1) ] + [ 5/(x-1) ] + ( 10/(x²-1) ] = (7x+13)/(x²-1) 

Bonne journée