urgent resoudre les operation et reduis au maximum (2/3-1/9)+(2-2/5) 2/3+(4/3-2/3+2) calcule astucieusement A=25 au carréx4 au carréx5,18

Bonjour TaisaaOMG

resoudre les operation et reduis au maximum
(2/3-1/9)+(2-2/5)

[tex](\dfrac{2}{3}-\dfrac{1}{9})+(2-\dfrac{25}{5})=(\dfrac{2\times3}{3\times3}-\dfrac{1}{9})+(2-5)\\\\(\dfrac{2}{3}-\dfrac{1}{9})+(2-\dfrac{25}{5})=(\dfrac{6}{9}-\dfrac{1}{9})+(-3)\\\\(\dfrac{2}{3}-\dfrac{1}{9})+(2-\dfrac{25}{5})=\dfrac{5}{9}-3\\\\(\dfrac{2}{3}-\dfrac{1}{9})+(2-\dfrac{25}{5})=\dfrac{5}{9}-\dfrac{27}{9}\\\\\boxed{(\dfrac{2}{3}-\dfrac{1}{9})+(2-\dfrac{25}{5})=-\dfrac{22}{9}}[/tex]

2/3+(4/3-2/3+2)

[tex]\dfrac{2}{3}+(\dfrac{4}{3}-\dfrac{2}{3}+2)=\dfrac{2}{3}+\dfrac{4}{3}-\dfrac{2}{3}+2\\\\\dfrac{2}{3}+(\dfrac{4}{3}-\dfrac{2}{3}+2)=\dfrac{4}{3}+2\\\\\dfrac{2}{3}+(\dfrac{4}{3}-\dfrac{2}{3}+2)=\dfrac{4}{3}+\dfrac{6}{3}\\\\\boxed{\dfrac{2}{3}+(\dfrac{4}{3}-\dfrac{2}{3}+2)=\dfrac{10}{3}}[/tex]

calcule astucieusement
A=25 au carréx4 au carréx5,18

[tex]A=25^2\times4^2\times5,18\\\\A=(25\times4)^2\times5,18\\\\A=100^2\times5,18\\\\A=10\ 000\times5,18\\\\\boxed{A=51\ 800}[/tex]